A can do a certain job in 12 days. B is 60% more efficient than A. To

1.	A can do a certain job in 12 days. B is 60% more efficient than A. To do the same job B alone would take?1. \(7\frac{1}{2} \) days2. 8 days3. 10 days4. 7 days
Answer» Correct Answer - Option 1 : \(7\frac{1}{2} \) days Given: A can do a certain job in 12 days. B is 60% more efficient than A. Formula used: work = efficiency × days Calculation: Let efficiency of A be 100. The efficiency of B will be 160. Ratio of efficiency A and B = 100 : 160 = 5 : 8 Total work = efficiency ratio of A × total days taken by A to finish work ⇒ 5 × 12 = 60 unit Time taken by B to finish work = total work/efficiency ratio of B ⇒ 60/8 = \(7\frac{1}{2} \) days ∴ B will finish the job in \(7\frac{1}{2} \) days.

A can do a certain job in 12 days. B is 60% more efficient than A. To do the same job B alone would take?1. \(7\frac{1}{2} \) days2. 8 days3. 10 days4. 7 days

Answer» Correct Answer - Option 1 : \(7\frac{1}{2} \) days

Given:

A can do a certain job in 12 days.

B is 60% more efficient than A.

Formula used:

work = efficiency × days

Calculation:

Let efficiency of A be 100.

The efficiency of B will be 160.

Ratio of efficiency A and B = 100 : 160 = 5 : 8

Total work = efficiency ratio of A × total days taken by A to finish work

⇒ 5 × 12 = 60 unit

Time taken by B to finish work = total work/efficiency ratio of B

⇒ 60/8 = \(7\frac{1}{2} \) days

∴ B will finish the job in \(7\frac{1}{2} \) days.

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