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A can do a piece of work in 30 hours and earns Rs 60,000. But after completing one-third of the work he reduces his speed to two-third and after completing another one-third part of the work, he reduces his speed to one-third of his initial speed. If there is penalty of Rs 1,000 on delay of each hour then find the total time taken by A to complete the work and wages earned after penalty.1. 60 hours, Rs 30,0002. 45 hours, Rs 45,0003. 55 hours, Rs 35,0004. 40 hours, Rs 50,000 |
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Answer» Correct Answer - Option 3 : 55 hours, Rs 35,000 Given: Time taken by A to complete a work = 30 hours Amount earned through the work = Rs 60,000 The penalty on delaying work by each hour = Rs 1,000 Formula used: Efficiency = Total work/Total time Calculations: Let the total work be 90 units. ⇒ Efficiency of A = 90/30 ⇒ 3 units/hour. According to question, A completed one-third work at usual pace (3 units/hour), ⇒ Time to complete one-third work = 30/3 ⇒ 10 hours A completed another one-third work at two-third of the usual pace (2 units/hour), ⇒ Time to complete another one-third work = 30/2 ⇒ 15 hours A completed remaining work at one-third of the usual pace (1 units/hour), ⇒ Time to complete another one-third work = 30/1 ⇒ 30 hours Total time taken by A to complete whole work = (10 + 15 + 30) ⇒ 55 hours As there is delay of 25 hours, ⇒ Penalty = Rs 25,000 Amount earned after penalty = (60,000 - 25,000) ⇒ Rs 35,000 ∴ The total time taken by A to complete the work and wages earned after penalty are 55 hours and Rs 35,000 respectively. |
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