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A cannon ball is fired at an angle theta, 0 lt theta lt pi//2, with the horizontal. If v is the initial velocity of the cannon ball, the height h of the ball at time t, ignoring the air resistance, is given by : h=(v sin theta) t-4.9t^(2). The value of theta so that the horizontal range of the ball is maximum is : |
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Answer» `pi//6` |
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