A cannon is fixed with a smooth massive trolley car at an angle theta as shown in the figure.The trolley car slides from rest down the inclined plane of angle of inclination beta. The muzzle velocity of the shell fired at t=y_(0) from the cannon is u,such that the shell moves perpendicular to the inclined just after the firing. the difference in range of the shell relative to the trolley car and ground is:

A cannon is fixed with a smooth massive trolley car at an angle theta

1.	A cannon is fixed with a smooth massive trolley car at an angle theta as shown in the figure.The trolley car slides from rest down the inclined plane of angle of inclination beta. The muzzle velocity of the shell fired at t=y_(0) from the cannon is u,such that the shell moves perpendicular to the inclined just after the firing. the difference in range of the shell relative to the trolley car and ground is:
Answer» `(u^(2)sin 2theta)/(G COS BETA)` `(u^(2)cos theta)/(2g sin beta)` `(u^(2) sin theta sin beta)/(2g)` `(2U^(2) sin theta cos (theta-beta))/(g cos^(2) g)` Solution :Distance moved by shell `=(V_(0)cos theta)t+1/2g sin betat^(2)` `t=(2U sin theta)/(g cos beta)` on SOLVING `X=(2U^(2) sin theta)/(g cos^(2) beta)cos(theta-beta)`