InterviewSolution
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InterviewSolution
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A cannot engine has efficiency `(1)/(6)`. If temperature of sink is decreased by `62^(@)C` then its efficiency becomes `(1)/(3)` then the temperature of source and sink:A. `33^(@)C, 67^(@)C`B. `37^(@), 99^(@)C`C. `67^(@)C, 33^(@)C`D. `97K, 37 K` |
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Answer» Correct Answer - B `(W)/(Q) = (1)/(6)` `1 = (T_(L))/(T_(H)) = (1)/(6)` `(T_(L))/(T_(H)) = n (5)/(6)` If sink temp decrease by `62^(@)`C then `1 - (T_(L) - 62)/(T_(H)) = (2)/(6) implies (T_(L) - 62)/(T_(H)) = (2)/(3)` `2T_(H) = 3T_(L) - 186 implie 2T_(H) = 3 xx (5)/(6) T_(H) - 186` `2T_(H) - (5)/(2) T_(H) = - 186 implies (5 - 4)/(2) T_(H) = 186` `T_(H) = 186 xx 2 = 372 K = 99^(@) C` `T_(L) = (5)/(6) xx 372 = 310 K = 37^(@)C` |
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