Limiting molar conductivity of `NH_(4)OH` [i.e., `Lambda_(m)^(@)(NH_(4)OH)`] is equal to:A. `A_(m)^(@) (NH_(4)OH) +A_(m)^(@)(NH_(4)Cl)-A_(m)^(@)(HCl)`B. `A_(m)^(@) (NH_(4)Cl) +A_(m)^(@)(NHOH)-A_(m)^(@)(NaCl)`C. `A_(m)^(@)(NH_(4)Cl)+A_(m)^(@)(NaCl)-A_(m)^(@)(NaOH)`D. `A_(m)^(@)(NAOH)+A_(m)^(@)(NaCl)-A_(m)^(@)(NH_(4)Cl)`

Limiting molar conductivity of `NH_(4)OH` [i.e., `Lambda_(m)^(@)(NH_(4

1.	Limiting molar conductivity of `NH_(4)OH` [i.e., `Lambda_(m)^(@)(NH_(4)OH)`] is equal to:A. `A_(m)^(@) (NH_(4)OH) +A_(m)^(@)(NH_(4)Cl)-A_(m)^(@)(HCl)`B. `A_(m)^(@) (NH_(4)Cl) +A_(m)^(@)(NHOH)-A_(m)^(@)(NaCl)`C. `A_(m)^(@)(NH_(4)Cl)+A_(m)^(@)(NaCl)-A_(m)^(@)(NaOH)`D. `A_(m)^(@)(NAOH)+A_(m)^(@)(NaCl)-A_(m)^(@)(NH_(4)Cl)`
Answer» Correct Answer - B `NH_(4)Cl+NaOH to NH_(4)OH+NaCl` `pi_(m_(NH_(4)Cl))+pi_(m_(NaOH))-pi_(m_(NaCl))=pi_(m_(NH_(4)OH))`

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