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A capacitor `C = (2.0 +- 0.1)muF` is charged to a voltage `V = (20 +- 0.5)` volt. Calculate the charge Q with error limits. |
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Answer» `Q = CV = 2.0xx20 = 40` micro coulomb `=40xx10^(-6)C` `(DeltaQ)/(Q) = (DeltaC)/(C ) +(DeltaV)/(V) = (0.1)/(2.0)+(0.5)20 = (3)/(40)` `DeltaQ = (3)/(40)xxQ = 3.0 muC` `Hence, Q = (40 +- 3.0)xx10^(-6)C` |
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