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A capacitor charged from a 50 V d.c. supply is found to have charge of `10 muC`. What is the capacitance of the capacitor and how much energy is stored in it? |
Answer» As `C = (q)/(V) = (10xx10^(-6))/(50) = 0.2 muF` Energy stored , `U = (1)/(2) CV^(2)` `= (1)/(2) xx 0.2 xx10^(-6)xx(50)^(2) = 2.5 xx10^(-4) J`. |
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