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A capacitor has some dielectric between its plates, and the capacitor is connected to a DC source. The battery is now disconnected and then the dielectric is removed. State whether the capacitance, the energy stored in it, electric field, charge stored and the voltage will increase ro remain constant. |
Answer» When the capacitance is connected to dc source, it gets charged. The battery is now disconnected So no more charge can flow in, i.e., charged stored will stay constant. On removing dielectric, capacitance decreases . Energy stored `= (Q^(2))/(2C)` will increase, Pot, `V = (Q)/(C)` would increase `E = (V)/(d)` will increase. |
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