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A capacitor has some dielectric between its plates, and the capacitor is connected to a DC source. The battery is now disconnected and then the dielectric is removed. State whether the capacitance, the energy stored in it, electric field, charge stored and the voltage will increase, decrease or remain constant. |
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Answer» C will decrease Energy stored =1/2CV2 and hence will increase. Electric field will increase. Charge stored will remain the same. V will increase. |
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