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A capacitor is charged and then made to discharge through a resistance. The time constant is τ. In what time will the potential difference across the capacitor decrease by 10%? (a) τ In (0.1) (b) τ In (0.9) (c) τ In (10/9) (d) τ In (11/10) |
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Answer» Correct Answer is:(c) τ In (10/9) Q = Q0e -t/τ and potential difference across C is proportional to Q. For the p.d. to fall by 10%, Q must fall by 10%. Q = 0.9Q0 = Q0e -t/τ or et/τ = 10/9 or t/τ = In (10/9). |
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