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A capacitor loses a certain fraction of its charge in 30 s because of humidity in the air giving rise to leakage between its terminals. When a 4 MΩ resistance is connected between its terminals, in the presence of humidity, the same fraction of charge is lost in 7.5 s. Find the leakage resistance due to humidity (in MΩ)

Answer» A capacitor loses a certain fraction of its charge in 30 s because of humidity in the air giving rise to leakage between its terminals. When a 4 MΩ resistance is connected between its terminals, in the presence of humidity, the same fraction of charge is lost in 7.5 s. Find the leakage resistance due to humidity (in MΩ)


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