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A capacitor loses a certain fraction of its charge in 30 s because of humidity in the air giving rise to leakage between its terminals. When a 4 MΩ resistance is connected between its terminals, in the presence of humidity, the same fraction of charge is lost in 7.5 s. Find the leakage resistance due to humidity (in MΩ) |
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Answer» A capacitor loses a certain fraction of its charge in 30 s because of humidity in the air giving rise to leakage between its terminals. When a 4 MΩ resistance is connected between its terminals, in the presence of humidity, the same fraction of charge is lost in 7.5 s. Find the leakage resistance due to humidity (in MΩ) |
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