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A capacitor of `10 muF` stores charge 10 mC at given potential difference. If capacitace of capacitor is double then find charge shared for same potential difference. |
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Answer» `(C_(1))/(C_(2)) = (Q_(1))/(Q_(2))` `Q_(2) = (C_(2))/(C_(1)) xx Q_(1)`. `= 20mC` |
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