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A capacitor of `20 muF` is charged to `500` volts and connected in parallel ith another capacitor of `10 muF` and charged to `200` volts. The common potential isA. 500VB. 400VC. 300VD. 200V

Answer» Correct Answer - B
`C_(1)=20mF,V_(1)=500V,`
`C_(2)=10mF,V_(2)=200V`
V = ?
`V=(C_(1)V_(1)+C_(2)V_(2))/(C_(1)+C_(2))`
`=(20xx10^(-6)xx500+10xx10^(-6)xx200)/(30xx10^(-6))`
= 400 V


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