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A capacitor of `20 muF` is charged to `500` volts and connected in parallel ith another capacitor of `10 muF` and charged to `200` volts. The common potential isA. 500VB. 400VC. 300VD. 200V |
Answer» Correct Answer - B `C_(1)=20mF,V_(1)=500V,` `C_(2)=10mF,V_(2)=200V` V = ? `V=(C_(1)V_(1)+C_(2)V_(2))/(C_(1)+C_(2))` `=(20xx10^(-6)xx500+10xx10^(-6)xx200)/(30xx10^(-6))` = 400 V |
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