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A capacitor of capacitance `C_1 = 1.0muF` charged upto a voltage `V = 110 V` is connected in parallel to the terminals of a circuit consisting of two uncharged capacitors connected in series and possessing the capacitance `C_2 = 2.0 muF` and `C_3 = 3.0muF`. What charge will flow through the connecting wires? |
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Answer» Correct Answer - C `C_23=(2xx3)/(2+3)=1.2muF` ` q_("total")=C_1V=110muC` Common potential in parallel is given by `V=("Total charge")/("Total capacity")` `=110/(1+1.2)=50V` `q_23=(C_23)V=60muC` So, this much charge flows through the switch. |
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