A capacitor of capacitance C = 3.0 pm 0.1 muF is charged to a voltage of V = 18 pm 0.4 Volt. Calculate the charge Q[Use Q = CV].

A capacitor of capacitance C = 3.0 pm 0.1 muF is charged to a voltage

1.	A capacitor of capacitance C = 3.0 pm 0.1 muF is charged to a voltage of V = 18 pm 0.4 Volt. Calculate the charge Q[Use Q = CV].
Answer» SOLUTION :`(C +DeltaC) = (3.0 PM 0.1) muF` `(V+DeltaV) = (18pm0.4)V` Q = CV `Q = 3.0 xx 10^(-6) xx 18 = 54 xx 10^(-6)` COULOMB Error in `V = (DeltaV)/(V) xx 100 = (0.4)/(18) xx 100 = 2.2%` Error in Q = Error in C + Error in V = 3.3% + 2.2% = 5.5% `:.` Charge Q = `(54 xx 10^(6) pm 5.5%)` coulomb