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A capacitor of capacity `C_(0)` is charged to certain potential and enrgy stored in it is `U_(0)`. Now this capacitor is connected in parrallel to uncharged capacitor of capacitance. `C`. Find the loss of energy. |
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Answer» `U_(0)=(1)/(2)C_(0)V_(0)^(2) C_(0)V_(0)^(2)` `DeltaU=(1)/(2)(C_(1)C_(2))/(C_(1)+C_(2))(VG_(1)-V_(2))^(2)` `=(1)/(2)(C-(0)C)/((C_(0)+C))(V_(0)-0)^(2)=((c)/(C_(0)+C))((1)/(2)C_(0)V_(0)^(2))` `=(CU_(0))/(C_(0)+C)` |
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