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A capacity of capacity `C_(1)` is charged up to `V` volt and then connected to an uncharged capacitor of capacity `C_(2)`. Then final potential difference across each will beA. `(C_(2)V)/(C_(1)+C_(2))`B. `(C_(1)V)/(C_(1)+C_(2))`C. `(1+(C_(2))/(C_(1)))V`D. `(1-(C_(2))/(C_(1)))V` |
Answer» Correct Answer - B |
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