A capacity of capacity `C_(1)` is charged up to `V` volt and then connected to an uncharged capacitor of capacity `C_(2)`. Then final potential difference across each will beA. `(C_2V)/(C_1+C_2)`B. `(C_1V)/(C_1+C_2)`C. `(1+C_2/C_1)`D. `(1-C_2/C_1)V`

A capacity of capacity `C_(1)` is charged up to `V` volt and then conn

1.	A capacity of capacity `C_(1)` is charged up to `V` volt and then connected to an uncharged capacitor of capacity `C_(2)`. Then final potential difference across each will beA. `(C_2V)/(C_1+C_2)`B. `(C_1V)/(C_1+C_2)`C. `(1+C_2/C_1)`D. `(1-C_2/C_1)V`
Answer» Correct Answer - B `V_"common"=(C_1V_1+C_2V_2)/(C_1+C_2)=(because V_2=0)` `rArr V_"common"=(C_1V)/(C_1+C_2)`

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A capacity of capacity `C_(1)` is charged up to `V` volt and then connected to an uncharged capacitor of capacity `C_(2)`. Then final potential difference across each will beA. `(C_2V)/(C_1+C_2)`B. `(C_1V)/(C_1+C_2)`C. `(1+C_2/C_1)`D. `(1-C_2/C_1)V`

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