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InterviewSolution
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A capaitor of capacitance `C_(1) = 1.0 muF` withstands teh maximum voltage `V_(1) = 6.0 kV` while a capacitor of capacitance `C_(s) = 2.0 muF`, the maximum voltage `V_(s) = 4.0 kV`. What voltage will the system of these two capacitors withsatand if they are connected in sereis ? |
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Answer» Amount of charge, that the capacitor of capacitance`C_(1)` can withstand, `q_(1) = C_(1) V_(1)` and similarly the charge, that the capacitor of capacitance `C_(2)` can withstand , `q_(2) = C_(2) V_(2)`. But in series combination, charge on both the capacitors will be same, so `q_(max)`, that the conservation can withstand `= C_(1) V_(1)`, as `C_(1) V_(1) lt C_(2) V_(2)`, from the numberical data, given. Now, net capacitance of the system, `C_(0) = (C_(1) C_(2))/(C_(1) + C_(2))` and hence, `V_(max) = (q_(max))/(C_(0)) = (C_(1) V_(1))/(C_(1) C_(2)//C_(1) + C_(2)) = V_(1) (1 + (C_(1))/(C_(2))) = 9 kV` |
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