A capilaary tube of radius 0.35cm is dipped in water. To what height will water inside the capilary raise? (Given S.T. of water =0.072 Nm^(-1), theta between water-glass contact theta=0^(@))

A capilaary tube of radius 0.35cm is dipped in water. To what height w

1.	A capilaary tube of radius 0.35cm is dipped in water. To what height will water inside the capilary raise? (Given S.T. of water =0.072 Nm^(-1), theta between water-glass contact theta=0^(@))
Answer» Solution :We KNOW that, for water-glass, `theta=0^(@), cos 0^(@)=1` and `T=1/2 (pgr(h+r/3))/(cos theta)=1/2 xx 10^(3) xx 9.8 xx 0.035 xx 10^(-2)(3H+0.035 xx 10^(-2))/(3)` `=0.072=0.517(3h+0.035 xx 10^(-2))` i.e, `3h+0.035 xx 10^(-2)=0.126` 3h=(0.126)-(0.0035) `h=(0.2157)/(3)=h=0.0419m`