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A capilaary tube of radius 0.35cm is dipped in water. To what height will water inside the capilary raise? (Given S.T. of water =0.072 Nm^(-1), theta between water-glass contact theta=0^(@))

Answer» <html><body><p></p>Solution :We <a href="https://interviewquestions.tuteehub.com/tag/know-534065" style="font-weight:bold;" target="_blank" title="Click to know more about KNOW">KNOW</a> that, for water-glass, `theta=0^(@), cos 0^(@)=<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>` <br/> and `T=1/2 (pgr(h+r/3))/(cos theta)=1/2 xx 10^(3) xx 9.8 xx 0.035 xx 10^(-2)(<a href="https://interviewquestions.tuteehub.com/tag/3h-310742" style="font-weight:bold;" target="_blank" title="Click to know more about 3H">3H</a>+0.035 xx 10^(-2))/(3)` <br/> `=0.072=0.517(3h+0.035 xx 10^(-2))` <br/> i.e, `3h+0.035 xx 10^(-2)=0.126` <br/> 3h=(0.126)-(0.0035) <br/> `h=(0.2157)/(3)=h=0.0419m`</body></html>


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