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A capillary tube of diameter 0.20 mm is lowered vertically into water in a vessel. What should be the pressure inN//m^(2)to be applied on the water in the capillary tube so that water level in the tube is same as that in the vessel ? (surface tension of water is 0.07 N/m and atm pressure is10^(5)N//m^(2)) |
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Answer» <P>`10^(3)` `P_(i)=P_(o)+(2T)/(R)` `=10^(5)+(2xx0.07)/(0.1xx10^(-3))` `=10^(5)+14xx10^(2)` `=1,00,000+1400` `=10.1.4xx10^(3)Nm^(-2)` |
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