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A capillary tube of diameter 0.20 mm is lowered vertically into water in a vessel. What should be the pressure inN//m^(2)to be applied on the water in the capillary tube so that water level in the tube is same as that in the vessel ? (surface tension of water is 0.07 N/m and atm pressure is10^(5)N//m^(2)) |
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>`10^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`99xx10^(3)`<br/>`100xx10^(3)`<br/>`101.4xx10^(3)`</p>Solution :Consider the <a href="https://interviewquestions.tuteehub.com/tag/meniscus-1093619" style="font-weight:bold;" target="_blank" title="Click to know more about MENISCUS">MENISCUS</a> of <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> of water in capillary as bubble , <br/>`P_(i)=P_(o)+(2T)/(R)`<br/>`=10^(5)+(2xx0.07)/(0.1xx10^(-3))`<br/>`=10^(5)+14xx10^(2)`<br/>`=1,00,000+1400`<br/>`=10.1.4xx10^(3)Nm^(-2)`</body></html> | |