1.

A capillary tube of diameter 0.20 mm is lowered vertically into water in a vessel. What should be the pressure inN//m^(2)to be applied on the water in the capillary tube so that water level in the tube is same as that in the vessel ? (surface tension of water is 0.07 N/m and atm pressure is10^(5)N//m^(2))

Answer»

<P>`10^(3)`
`99xx10^(3)`
`100xx10^(3)`
`101.4xx10^(3)`

Solution :Consider the MENISCUS of SURFACE of water in capillary as bubble ,
`P_(i)=P_(o)+(2T)/(R)`
`=10^(5)+(2xx0.07)/(0.1xx10^(-3))`
`=10^(5)+14xx10^(2)`
`=1,00,000+1400`
`=10.1.4xx10^(3)Nm^(-2)`


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