A capillary tube of length 5 cm and diameter 1 mm is connected to a tank horizontally. The rate of flow of water is 10 ce per minute. Calculate the rate of flow of water through another capillary tube of diameter 2 mm and length 50 cm is connected in series with the first capillary?

A capillary tube of length 5 cm and diameter 1 mm is connected to a ta

1.	A capillary tube of length 5 cm and diameter 1 mm is connected to a tank horizontally. The rate of flow of water is 10 ce per minute. Calculate the rate of flow of water through another capillary tube of diameter 2 mm and length 50 cm is connected in series with the first capillary?
Answer» Solution :` Q = 10 xx 10 ^(-6) // 60 m^(3)//s , P = 8 eta L Q //pi r ^(4), P = 8 eta xx 5 xx 10 ^(-2)xx 10 xx 10 ^(-6) l ( 0.5 xx 10 ^(-3) ) ^(4)xx 60=(8 eta xx 1.33 xx 10 ^(5) //pi )` When in SERIES ` P= P_1 +P_2 = ( 8 eta l_1Q_1//pi r_1^(4))+(8 eta l_2 Q_2) //pi r_2^(4)` SIMPLIFYING `Q_2 = 1.02 xx 10 ^(-7)m^(3)//s`