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A capillary tube of radius 0.25 mm is dipped vertically in a liquid of density `800kgm^(-3)` and of surface tension `3xx10^(-2)Nm^(-2)`. The angle of contact of liquid -glass is given by `costheta=0.3` If `g=10ms^(-2)` the rise of liquid in the capillary tube is.. CmA. 9B. 0.9C. `9xx10^(-3)`D. `0.09`

Answer» Correct Answer - B
`T=(rhdg)/(2costheta)`


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