1.

A capillary tube of radus r is immersed in water and water rises in it to a height h. The mass of water in the capillary tube is 5g . Another capillary tube of radius 2r is immersed in water. The mass of water that will rise in this tube is …….

Answer»

`2.5g`
`5.0g`
10 g
20 g

Solution :`H=(2Tcostheta)/(rrhog)`
MASS of water in the FIRST tube ,
`m=pir^(2)hrho=pir^(2)xx((2Tcostheta)/(rrhog))xxdelta`
`=(2pirTcostheta)/(g)`
`thereforempropttr therefore(m.)/(m)=(2r)/(r)=2`
or `m.=2m=2xx5g=10g`


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