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A capillary tube with inner cross-section in the form of a square of side a is dipped vertically in a liquid of density `rho` and surface tension `rho` which wet the surface of capillary tube with angle of contact `theta` . The approximate height to which liquid will be raised in the tube is : (Neglect the effect of surface tension at the corners of capillary tube)A. `(2sigma cos theta)/(arhog)`B. `(4sigma cos theta)/(arhog)`C. `(8sigma cos theta)/(arhog)`D. None of these |
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Answer» Upward force by capilary tube on top surface of liquid is `f_(up)=4 sigma a cos theta` If liquid is raised to a height h then we use `4 sigma cos theta=ha^(2) rhog` or `h=(4sigma cos theta)/(arhog)` Ans. |
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