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A cappilary of diameter d mm is dipped in water such that the water rises to a height of 30 mm. If the radius of the capillary is made ((2)/(3)) of its previous value, then compute the height up to which water will rise in the new capillary ? |
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Answer» Solution :We KNOW the height of the CAPILLARY RISE `H = (2T cos theta)/(r dg)` where T = surface tension, r = RADIUS , d = density , g = acceleration due to gavity Now, `h_1r_1 = h_2r_2implies (h_2)/(h_1) = (r_1)/(r_2)` Here , `r_2 = 2/3 r_1 and h_1 = 30 mm` `h_2 = (r_1)/((2/3)r_1) xx 30 = 3/2 xx 30` `h_2 = 45 mm`. |
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