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A car `A` moves with velocit `20 m s^(-1)` and car `B` with velocity `15 m s^(-1)` as shown is. Find the relativety B` w.r.t. `A` w.r.t. `B`. . |
Answer» Let us assume that right direction is positive. We are given: `v_(A)=20 m s^(-1), v_(B)=15 ms^(-1)`, Relative velocity of `B` w.r.t `A`: `v_(B//A)=v_(B)-v_(A)=15-20=-5 m s^(-1)` (Negative sign indecates that this relative velocity is in the left direction.) Relative velocity of `A` w.r.t `B`: `v_(A//B)=v_(A)-v_(B)=20-15=5 m s^(-1)` (Positive sign indicates that this relative velocity is in the right derction.) Hence, the separation between`A` and `B` is dereasing with time, here the velocity of approach of `A` w.r.t `B` is `5 m s^(-1)`. |
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