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a car aacelerates uniformly from 18km/h to 36 km/h in 5secounds calculate 1) the acceleration 2) the distance covered by the car in that time |
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Answer» INITIAL velocity, u = 18×5/18=5m/s Final velocity v=36×5/18=10m/s Time, t=5s V=u+at 10=5+5a Acceleration A=1m/S SQUARE Distance, s=ut+1/2at ^2 5×5+1/2*1*5*5 25+1/2*25 =25+12.5 =37. 5m Please MARK this as brainliest. Hope it use clear |
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