1.

A car accelerates from 6 ms –1 to 16 ms –1 in 10 sec. Calculate (a) the acceleration and (b) the distance covered by the car in that time.

Answer»

Initial velocity = u 

u = 6m/s 

Final velocity = v 

V = 16m/s 

Time = t = 10 s 

• Acceleration = a 

a = \(\frac{(v-u)}{t}\)

=  \(\frac{(16-6)}{10}\)

= 1 m/s2 

• Distance = s

s= \(\frac{(v^2-u^2)}{2a}\)

s = \(\frac{256-36}{2\times1}\)

= 110 m


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