A car accelerates from rest at a constant rate `alpha` for some time, after which it decelerates at a constant rate `beta,` to come to rest. If the total time elapsed is t seconds. Then evalute (a) the maximum velocity reached and (b) the total distance travelled.A. `((alpha^(2)+beta^(2))/(alpha beta))t`B. `((alpha^(2)-beta^(2))/(alpha beta))t`C. `((alpha+beta)t)/(alpha beta)`D. `(alpha betat)/(alpha +beta)`

A car accelerates from rest at a constant rate `alpha` for some time,

1.	A car accelerates from rest at a constant rate `alpha` for some time, after which it decelerates at a constant rate `beta,` to come to rest. If the total time elapsed is t seconds. Then evalute (a) the maximum velocity reached and (b) the total distance travelled.A. `((alpha^(2)+beta^(2))/(alpha beta))t`B. `((alpha^(2)-beta^(2))/(alpha beta))t`C. `((alpha+beta)t)/(alpha beta)`D. `(alpha betat)/(alpha +beta)`
Answer» Correct Answer - B

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