A car accelerates uniformly from 18 km h to 36 km h in 5 min calculate

1.	A car accelerates uniformly from 18 km h to 36 km h in 5 min calculate acceleration and distance cover by car in that time
Answer» Given , INITIAL velocity (U) = 18km/hr = 5m/s Final velocity (v) = 36km/hr = 10m/s Time (t) = 5min = 300secs. Now ACCELERATION (a) = (v)-(u)/(t) = 10-5/300 = 1/60 per second square Therefore, Distance(s) = u.t+1/2.a.t.t = 5300+1/21/60300300 = 2250M

A car accelerates uniformly from 18 km h to 36 km h in 5 min calculate acceleration and distance cover by car in that time

Answer»

Given ,

INITIAL velocity (U) = 18km/hr = 5m/s

Final velocity (v) = 36km/hr = 10m/s

Time (t) = 5min = 300secs.

Now

ACCELERATION (a) = (v)-(u)/(t)

= 10-5/300

= 1/60 per second square

Therefore,

Distance(s) = u.t+1/2.a.t.t

= 5*300+1/2*1/60*300*300