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.A car accelerates uniformly from 30 m/s to 48 m/s in 3 seconds.Calculate the acceleration of the car anddistance covered by the car in first 3 seconds. |
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Answer» Answer: ACCELERATION is equals to 6 m/s^2 distance COVERED is equals to 117 m Explanation: given: u=30m/s. v=48m/s t=3s v=u+at 48=30+a×3 a=6m/s^2 S=ut+1/2×at^2 S=90+27 S=117m |
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