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A car complete the first half of its journey with speed `v_1`, and the rest half with speed `v_2`. The average speed of the car in whole journey: |
Answer» Let total distance covered in journey `= d` Speed of car in first half covering distance `d/2 = v_1` Time taken by the car during first half of the journey `(t_1)= (d/2)/(v_1) = d/(2v_1)` Speed of car in second half covering distance `d/2 = v_2` Time taken by the car during second half of the journey `(t_2)= (d/2)/(v_2) = d/(2v_2)` `:.` Average speed ` = d/(t_1+t_2) = d/(d/(2v_1)+d/(2v_2))` ` =2/(1/v_1+1/v_2) = (2v_1v_2)/(v_1+v_2)` So, average speed of the car is `(2v_1v_2)/(v_1+v_2)`. |
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