1.

A car costing Rs. 5,00,000 of a person depreciated at the rate of 15% in the first year, 13% in the second year and so on. House of that person, costing Rs. 7,00,000 appreciated at the rate of 10% in the first year, 12% in the second year and so on. What was the change in total value of car, house at the end of 3 years? 1. Increase of Rs.1678342. Decrease of Rs. 1324363. Increase of Rs. 1122144. Increase of Rs 234116

Answer» Correct Answer - Option 3 : Increase of Rs. 112214
Original cost of a car and house = 500000 + 700000 = Rs. 12,00,000
 
New cost of car = 500000 × 0.85 × 0.87 × 0.89 = Rs. 329077.5
 
New cost of house = 700000 × 1.1 × 1.12 × 1.14 = Rs. 983136
 
∴  Total new cost = Rs. 13,12,213.5 
 
∴  Change = increase of Rs. 1,12,213.5 ≈ Rs. 1,12,214
 
Hence, option 3 is correct. 


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