A car is driven at constant speed on a rough road. The shock absorbers vibrate vertically. As we know, if the displacement varies sinusoidally, the oscillation will be a simple harmonic. When there is matching between the disturbance and the oscillating shockers, we call it as resonance. Consider the mass of the car and its contents M=1500 kgwith a man of mass m=75 kg, rising vertically S=0.1 m due to the peaks separated by lambda=10 m equally and the speed of the car being v and time period being T.Then: The frequency of oscillation of the car is proportional to:

A car is driven at constant speed on a rough road. The shock absorbers

1.	A car is driven at constant speed on a rough road. The shock absorbers vibrate vertically. As we know, if the displacement varies sinusoidally, the oscillation will be a simple harmonic. When there is matching between the disturbance and the oscillating shockers, we call it as resonance. Consider the mass of the car and its contents M=1500 kgwith a man of mass m=75 kg, rising vertically S=0.1 m due to the peaks separated by lambda=10 m equally and the speed of the car being v and time period being T.Then: The frequency of oscillation of the car is proportional to:
Answer» `sqrt((MG)/(MS))` `sqrt((mg)/(d))` `sqrt((3mg)/(2MS))` `sqrt((mg)/(MD))` ANSWER :A