A car is moving along a straight horizontal road with a speed v0.

1.	A car is moving along a straight horizontal road with a speed v0. If the coefficient of friction between the tyres and the road is μ, the shortest distance in which the car be stopped is?
Answer» Work done against frictional force equals the kinetic energy of the body. when a body of mass m, moves with velocity v, it has kinetic energy k= 1/2mv² , this energy is utilized in doing work against the frictional force between the tyres of the car and road. ∴ kinetic energy = work done against friction force 1/2m² =μ mgs where s is the distance in which the car is stopped and μ is coefficient of kinetic friction. Given v=v₀ s=v₀²/2μg

A car is moving along a straight horizontal road with a speed v0. If the coefficient of friction between the tyres and the road is μ, the shortest distance in which the car be stopped is?

Answer»

Work done against frictional force equals the kinetic energy of the body.
when a body of mass m, moves with velocity v, it has kinetic energy k= 1/2mv² , this energy is utilized in doing work against the frictional force between the tyres of the car and road.
∴ kinetic energy = work done against friction force 1/2m² =μ mgs
where s is the distance in which the car is stopped and μ is coefficient of kinetic friction.
Given v=v₀

s=v₀²/2μg

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A car is moving along a straight horizontal road with a speed v0​. If the coefficient of friction between the tyres and the road is μ, the shortest distance in which the car be stopped is?

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A car is moving along a straight horizontal road with a speed v0. If the coefficient of friction between the tyres and the road is μ, the shortest distance in which the car be stopped is?