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A car is moving along a straight horizontal road with a speed `v_(0)` . If the coefficient of friction between the tyres and the road is `mu` , the shortest distance in which the car can be stopped isA. `(V_(0)^(2))/(2mug)`B. `(V_(0)^(2))/(mug)`C. `((V_(0))/(mug))^(2)`D. `(2V_(0)^(2))/(mug)` |
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Answer» Correct Answer - A `O^(2)-V_(0)^(2)=2(-mug)xxs` `s=(V_(0)^(2))/(2mug)` |
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