A car is moving with a constant acceleration and initial velocity 2 ms^(-1)on a straight path. After 10 s it attains the velocity 12 ms^(-1). Then find the distance covered by it in this 10 s.

A car is moving with a constant acceleration and initial velocity 2 ms

1.	A car is moving with a constant acceleration and initial velocity 2 ms^(-1)on a straight path. After 10 s it attains the velocity 12 ms^(-1). Then find the distance covered by it in this 10 s.
Answer» 140 m 50 m 160 m 70 m Solution :`v _(0) = 2ms ^(-1) , v = 12 ms ^(-1) , t = 10s` `therefore a = (v -v _(0))/( t ) = (12 -2)/(10) = 1 ms ^(-2)` Now, `x = v _(0)t + 1/2 at ^(2)= (2) (10) + 1/2 (1) (10) ^(2) = 70 m`