A car is running at a speed of 15 km h-1 while another similar car is

1.	A car is running at a speed of 15 km h-1 while another similar car is moving at a speed of 30 km h-1. Find the ration of their kinetic energies.
Answer» Given, velocity of first car, v₁ = 15 km/h And velocity of second car, v₂ = 30 km/h Since masses are same, kinetic energy is directly proportional to the square of the velocity (Kav₂) Hence, ratio of their kinetic energies is: k₁/k₂ = v₁²/v₂² = 15²/(30)² = 15 x 15/30 x 30 = 1/4 = 1 : 4

A car is running at a speed of 15 km h-1 while another similar car is moving at a speed of 30 km h-1. Find the ration of their kinetic energies.

Answer»

Given, velocity of first car, v₁ = 15 km/h

And velocity of second car, v₂ = 30 km/h

Since masses are same, kinetic energy is directly proportional to the square of the velocity (Kav₂)

Hence, ratio of their kinetic energies is:

k₁/k₂ = v₁²/v₂² = 15²/(30)² = 15 x 15/30 x 30 = 1/4 = 1 : 4