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A car moves along a straight path with variable velocity as shown in the figure. When the car is at possiting A, its velocity is 10 m s^(-1)and when it is atposition B, its velocity is 20 m s^(-1). If the cartakes 5 seconds of time to move from A to B, find theacceleration of the car. |
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Answer» Solution : Initial POSITION of the car at position`A=u=10 m s^(-1)` Final velocity of the car at position `B=v=20m s^(-1)` The charge in velocity of the car, `Deltav=v-u=20 m s^(-1)-10 m s^(-1)` `= 10 m s^(-1)` Time take taken for the car to MOVE from A to B, `Deltat=5S` `:.` Accelertion of the car, `a=(Deltav)/(Detlat)=(10 m s^(-))/(5s)` `2 m s^(-2)` |
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