A car moving along a straight high-way with a speed of 35 m/s is broug

1.	A car moving along a straight high-way with a speed of 35 m/s is brought to stop within a distance of 200 m. What Is the retardation, and how long does it take for the car to stop?
Answer» Initial speed of the car, u = 35 ms^-1 Final speed of the car, v = 0 Let a be the retardation of the car. Then using the relation, v² = u² + 2as, we have 0 = (35)²+ 2a × 200 a = – (35 x 35)/(2 x 200) = – 3.06 ms^-2 Let t be the time taken by the car to come to stop. Then, v = u + at ; 0 = 35 – 3.06 × t or t = 35/3.06 = 11.43 s.

A car moving along a straight high-way with a speed of 35 m/s is brought to stop within a distance of 200 m. What Is the retardation, and how long does it take for the car to stop?

Answer»

Initial speed of the car, u = 35 ms^-1

Final speed of the car, v = 0

Let a be the retardation of the car.

Then using the relation,

v² = u² + 2as, we have 0 = (35)²+ 2a × 200

a = – (35 x 35)/(2 x 200) = – 3.06 ms^-2

Let t be the time taken by the car to come to stop. Then,

v = u + at ;

0 = 35 – 3.06 × t or

t = 35/3.06 = 11.43 s.