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A car , moving with a speed of `50 km//hr` , can be stopped by brakes after at least ` 6m `. If the same car is moving at a speed of `100 km//hr`, the minimum stopping distance isA. `12 m`B. `18 m`C. `24 m`D. `6 m` |
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Answer» Correct Answer - C `v^(2) = u^(2) +2as` `0 = (50 xx 5//18)^(2) +2a xx 6` `{:(a=-16m//s^(2),,,(a=retardation),):}` {:(`:."Again",,,v^(2)u^(2)+2as,):}` `0 = (100 xx 5//18^(2)) - 16 xx 2xx s` `S = (100 xx 5)^(2)` `S = ((100xx5)^(2))/(18 xx 18 xx 32) = 24.1 = 24 m` |
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