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A car moving with a velocity of 10m/s can be stopped by the application of a constant force F In a distance of 20m. If the velocity of the car is 30m/s. It can be stopped by this force inA. `(20)/(3)m`B. 20 mC. 60 mD. 180 m |
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Answer» Correct Answer - D `S prop u^(2)`. If u becomes 3 time, then S will become 9 times i.e., `9xx20=180 m` |
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