A car moving with a velocity of 72 KMPH stops its engine just at the foot of a hill. Ifthe car ascends a height of 12m, the energy lost in overcoming friction is (g = 10 m//s^(-2))

A car moving with a velocity of 72 KMPH stops its engine just at the f

1.	A car moving with a velocity of 72 KMPH stops its engine just at the foot of a hill. Ifthe car ascends a height of 12m, the energy lost in overcoming friction is (g = 10 m//s^(-2))
Answer» 0.4 0.25 0.6 0.5 Answer :A