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A car moving with constant acceleration covered the distance between two points `60.0 m` apart in `6.00 s.` Its speed as it passes the second point was `15.0 m//s.` (a) What is the speed at the first point? (b) What is the acceleration? (c) At what prior distance from the first was the car at rest? |
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Answer» Correct Answer - A::B::C (a) and (b) `60=u(6)+1/2xxaxx(6)^2` `15=u+(a)(6)` Solving these two equations,we get `u=5 m//s` and `a=5/3m//s^2` (C) `(5)^2=(2)(5/3)s (v^2=2as)` `:. s=7.5m` |
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