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A car of mass m is moving with a velocity v over a bridge. What will be the values of the force F at the highest point of a convex bridge and at the lowest point of a concave bridge? |
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Answer» Solution :A centripetal FORCE is required to move the car over a convex BRIDGE. The value of this centripetal force is ` (mv^(2))/(r )`. Here, r is the radius of curvature of the convex bridge At the highest point of the bridge. The resultant of the weight of the car mg and F will SUPPLY the necessary centripetal force. `therefore "" mg - F = (mv^(2))/(r )` or,` "" F = m(g- (v^(2))/(r))` ![]() (II) A centripetal force is required to move the car over concave bridge also. At the lowest point of the concave bridge, the resultant of the weight of the car mg and f will supply the necessary centripetal force. `therefore"" F - mg = (mv^(2))/(r ) "" or, f = m(g + (v^(2))/(r))`
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