A car of mass m starts from rest and acquires a velocity along east `upsilon = upsilonhati (upsilon gt 0)` in two seconds Assuming the car moves with unifrom acceleration the force exerted on the car is .A. `(mv)/(2)` eastward and is exerted by the car engine.B. `(mv)/(2)` eastward and is due to the friction on the tyres exerted by the road.C. more than `(mv)/(2)` eastward exerted due to the engine and overcomes the frictions of the road.D. `(mv)/(2)` exerted by the engine.

A car of mass m starts from rest and acquires a velocity along east `u

1.	A car of mass m starts from rest and acquires a velocity along east `upsilon = upsilonhati (upsilon gt 0)` in two seconds Assuming the car moves with unifrom acceleration the force exerted on the car is .A. `(mv)/(2)` eastward and is exerted by the car engine.B. `(mv)/(2)` eastward and is due to the friction on the tyres exerted by the road.C. more than `(mv)/(2)` eastward exerted due to the engine and overcomes the frictions of the road.D. `(mv)/(2)` exerted by the engine.
Answer» Correct Answer - B Given, mass of the car =m As car starts from rest `u =0` Velocity acquired along east `=vhati` Duration ` =t =2s` We know `v =u + at` `rArr vhati = 0 + a xx 2` `rArr a = (v)/(2) hati` Force `F = ma = (mv)/(2) hati` Hence, force acting on the car is `(mv)/(2)` towards east As external force on the system is only friction hence the force `(mv)/(v)` is by friction Hence, force by egine is internal force .

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