1.

A car starting from rest, moves some distance with constant acceleration 3 ms^(-2). Then it moves with constant deceleration 2 ms ^(-2) and finally becomes stationary. If the total time taken for the complete journey is 100 s, what was maximum velocity of the car e iu during the journey ?

Answer»

100
80
140
120

Solution :`t _(1) + t _(2) = 100 s`
For first case,` v . =v _(0) + a _(1) t _(1)`
`v.=0 +3t _(1) therefore t _(1) = (v.)/(3) ""…(1)`
For second case, `v=v. + a _(2) t _(2) `
`0=v. therefore t _(2) = (v.)/(2) ""…(2)`
`therefore t _(1) + t _(2) = (v.)/(3) + (v.)/(2)`
`therefore 100 = (5v .)/(6)`
`therefore v . = 120 ms ^(-1)`


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