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A car starts accelerating with an acceleration of `(1)/(3)m//s^(2)` when its speed was `18 km//h`. If the desplacement of car in `n^(th)` minute after it starts accelerating is `4.8km` then n is : |
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Answer» Correct Answer - 4 A car starts ……….. `Acc = (1)/(3)m//s^(2) = (60xx60)/(3)m//min^(2) = 1800m//min^(2)` initially velocity `18 km//h = (18000)/(60) = 300m//min` `4800=300+(1800)/(2)(2n-1)` `(2xx4500)/(1800) = 2n-1` `implies n = 3` |
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